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What will be the output of the following C code?
#include <stdio.h>
int main()
{
printf("C programming %s", "Class by\n%s Sanfoundry", "WOW");
}
int main()
{
printf("C programming %s", "Class by\n%s Sanfoundry", "WOW");
}
- a)C programming Class by
WOW Sanfoundry - b)C programming Class by\n%s Sanfoundry
- c)C programming Class by
%s Sanfoundry - d)Compilation error
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
What will be the output of the following C code? #include <stdio.h...
Explanation:
- The code snippet provided is trying to print a formatted string using the `printf` function.
- The format string given is "C programming %s", which contains one placeholder for a string.
- However, in the `printf` statement, there are three arguments provided.
- The first argument is the format string "C programming %s".
- The second argument is the string "Class by\n%s Sanfoundry".
- The third argument is the string "WOW".
- Since there is no placeholder in the format string for the third argument, it will be ignored by the `printf` function.
- So, the output will be "C programming Class by%s Sanfoundry".
Therefore, the correct output will be:
C programming Class by%s Sanfoundry
- The code snippet provided is trying to print a formatted string using the `printf` function.
- The format string given is "C programming %s", which contains one placeholder for a string.
- However, in the `printf` statement, there are three arguments provided.
- The first argument is the format string "C programming %s".
- The second argument is the string "Class by\n%s Sanfoundry".
- The third argument is the string "WOW".
- Since there is no placeholder in the format string for the third argument, it will be ignored by the `printf` function.
- So, the output will be "C programming Class by%s Sanfoundry".
Therefore, the correct output will be:
C programming Class by%s Sanfoundry
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Community Answer
What will be the output of the following C code? #include <stdio.h...
This program has only one %s within first double quotes, so it does not read the string “WOW”.
The %s along with the Sanfoundry is not read as a format modifier while new line character prints the new line.
Output:
$ cc pgm2.c
$ a.out
C programming Class by
%s Sanfoundry
The %s along with the Sanfoundry is not read as a format modifier while new line character prints the new line.
Output:
$ cc pgm2.c
$ a.out
C programming Class by
%s Sanfoundry
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What will be the output of the following C code? #include <stdio.h> int main() { printf("C programming %s", "Class by\n%s Sanfoundry", "WOW"); }a)C programming Class byWOW Sanfoundryb)C programming Class by\n%s Sanfoundryc)C programming Class by%s Sanfoundryd)Compilation errorCorrect answer is option 'C'. Can you explain this answer?
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